A body of mass $10\ kg$ at rest is acted upon simultaneously by two forces $4\ N$ and $3\ N$ at right angles to each other. The kinetic energy of the body at the end of $10\ sec$ is

Question

Dr. Abubacker · Accepted Answer

(d) Net force on body $= \sqrt{4^{2} + 3^{2}} = 5N$
$	herefore a = F/m = 5/10 = 1/2\ m/s^{2}$
Kinetic energy $= \frac{1}{2}mv^{2} = \frac{1}{2}m(at)^{2} = 125\ J$

Q. A body of mass $10\ kg$ at rest is acted upon simultaneously by two forces $4\ N$ and $3\ N$ at right angles to each other. The kinetic energy of the body at the end of $10\ sec$ is

Explanation

Reviewed by Dr. Abubacker

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