(d) From conservation of momentum.
Momentum before collision =Momentum after collision
$m_{1}u_{1} + m_{2}u_{2} = m_{1}v_{1} + m_{2}v_{2}$
20$\times 6 + 30 \times 0 = 20v + 30v$
$\therefore 20 \times 6 = 50v$
Or $v = \frac{120}{50} = 2.4ms^{- 1}$