(b) Let $M$be the mass of body moving with velocity v and m be mass of each broken part, velocity of one part which retraces back is v and that of second part is v’.
Momentum before breaking=momentum after breaking
$Mv = m( - v) + mv'$
Or $v^{'} = \frac{Mv + mv}{m}$
Since, M=2m,therefore
$v^{'} = \frac{(2m + m)v}{m} = 3v$