Q. In two separate collisions, the coefficient of restitutions $e_{1}$ and $e_{2}$ are in the ratio 3:1.In the first collision the relative velocity of approach is twice the relative velocity of separation ,then the ratio between relative velocity of approach and the relative velocity of separation in the second collision is
A) 1:6
B) 2:3
C) 3:2
D) 6:1
Explanation
(d) Coefficient of restitution is given by
$e = \ \frac{relative\ velocity\ of\ seperation}{relative\ velocity\ of\ approach}\ \ $
We have
$e_{1} = \frac{1}{2}$
And $e_{2} = \left( \frac{relative\ velocity\ of\ seperation}{relative\ velocity\ of\ approach} \right)_{2}$
Given ,$\frac{e_{1}}{e_{2}} = \frac{3}{1} \Rightarrow \frac{e_{2}}{e_{1}} = \frac{1}{3}$
$\therefore\left( \frac{relative\ velocity\ of\ seperation}{relative\ velocity\ of\ approach} \right)_{2} = \frac{1}{3} \times \frac{1}{2} = \frac{1}{6}$
Or $\left( \frac{relative\ velocity\ of\ approach\ }{relative\ velocity\ of\ seperation\ } \right)_{2} = \frac{6}{1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.