Q.
A bomb at rest explodes into 3 parts of the same mass.
The momentum of the 2 parts is $- 2p\widehat{I}$ and $p\widehat{j}$. The momentum of the third part will have a magnitude of
A) $p$
B) $\sqrt{3p}$
C) $p\sqrt{5}$
D) zero
Explanation
(c) Momentum of the third part will be equal to the resultant of momentum of two parts.
$p_{3} = \sqrt{p_{1}^{2} + p_{2}^{2}}$
$p_{3} = \sqrt{( - 2p)^{2} + p^{2}}$
$p_{3} = p\sqrt{5}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.