(b) Power $= \frac{Work\ done}{time} = \frac{Increase\ in\ K.E.}{time}$ $P = \frac{\frac{1}{2}mv^{2}}{t} = \frac{\frac{1}{2}{\times 10}^{3} \times (15)^{2}}{5} = 22500\ W$
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Ph.D. in Physics with 19+ years of teaching experience.