(d) Here $k = \frac{F}{x} = \frac{10}{1 \times 10^{- 3}} = 10^{4}\ N/m$ $W = \frac{1}{2}kx^{2} = \frac{1}{2} \times 10^{4} \times \left( 40 \times 10^{- 3} \right)^{2} = 8J$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.