Q. A spring of $40\ mm$ long is stretched by the application of a force. If $10\ N$ force required to stretch the spring through $1\ mm$, then work done in stretching the spring through $40\ mm$

A) $84\ J$
B) $68\ J$
C) $23\ J$
D) $8\ J$
Explanation

(d) Here $k = \frac{F}{x} = \frac{10}{1 \times 10^{- 3}} = 10^{4}\ N/m$
$W = \frac{1}{2}kx^{2} = \frac{1}{2} \times 10^{4} \times \left( 40 \times 10^{- 3} \right)^{2} = 8J$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.