Q. The graph between $\sqrt{E}$ and $1/p$ is ($E =$ kinetic energy and $p =$ momentum)
A)
B)
C)
D)
Explanation
(c) $P = \sqrt{2mE}$ it is clear that$\ P \propto \sqrt{E}$
So the graph between $P$ and $\sqrt{E}$ will be straight line
But graph between $\frac{1}{P}$ and $\sqrt{E}$ will be hyperbola
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.