The potential energy of a conservative system is given by $V(x) = \left( x^{2} - 3x \right)\ joule$. Then its equilibrium position is at

Question

Dr. Abubacker · Accepted Answer

(a) $V(x) = \left( x^{2} - 3x ight)\ J$
For a conservation field. Force, $F = - \frac{dV}{dx}$
$	herefore F = - \frac{d}{dx}\left( x^{2} - 3x ight) = - (2x - 3) = - 2x + 3$
At equilibrium position, $F = 0$
$- 2x + 3 = 0$
$x = \frac{3}{2}m = 1.5\ m$

Q. The potential energy of a conservative system is given by $V(x) = \left( x^{2} - 3x \right)\ joule$. Then its equilibrium position is at

Explanation

Reviewed by Dr. Abubacker

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