Q. A time t=0 s Particle starts moving along the x-axis. If its kinetic energy increases uniformly with time t, the net force acting on it must be proportional to
A) $\sqrt{t}$
B) Constant
C) t
D) $\frac{1}{\sqrt{t}}$
Explanation
(d) Given, $\frac{dK}{dt} = constant$
$K \propto t$
$v \propto \sqrt{t}$
$P = Fv = \frac{dK}{dt} = constant$
$F \propto \frac{1}{v}$
$F \propto \frac{1}{\sqrt{t}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.