Q. Three rings each of mass $M$ and radius $R$ are arranged as shown in the figure. The moment of inertia of the system about $YY'$ will be
A) $3\ MR^{2}$
B) $\frac{3}{2}\ MR^{2}$
C) $5\ MR^{2}$
D) $\frac{7}{2}\ MR^{2}$
Explanation
(d) Moment of inertia of system about $YY'$
$I = I_{1} + I_{2} + I_{3}$
$= \frac{1}{2}MR^{2} + \frac{3}{2}MR^{2} + \frac{3}{2}MR^{2}$
$= \frac{7}{2}MR^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.