Q. The speed of a homogeneous solid sphere after rolling down an inclined plane of vertical height $h$, form rest without sliding, is
A) $\sqrt{\frac{10}{7}gh}$
B) $\sqrt{gh}$
C) $\sqrt{\frac{6}{5}gh}$
D) $\sqrt{\frac{4}{3}gh}$
Explanation
(a) $v = \sqrt{\frac{2gh}{1 + \frac{K^{2}}{R^{2}}}} = \sqrt{\frac{2gh}{1 + \frac{2}{5}}} = \sqrt{\frac{10}{7}gh}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.