Q. A bullet of mass 5g moving with a velocity 10 $ms^{- 1}$ strikes a stationary body of mass 955g and enters it. The percentage loss of kinetic energy of the bullet is
A) 85
B) 0.05
C) 99.5
D) None of the above
Explanation
(d) According to conservation of momentum
$5 \times 10 = (955 + 5)v$
$v = \frac{50}{100} = \frac{1}{20}\ \ \ \ \ \ \ \therefore\%$ KE lost = $\frac{K_{1} - K_{2}}{K_{1}} \times 100 = 95.5\%$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.