A ball of mass $m_{1}$ is a moving with velocity $v$. It collides head on elastically with a stationary ball of mass $m_{2}$. The velocity of ball becomes $v/3$ after collision. Then the value of the ratio $\frac{m_{2}}{m_{1}}$ is

Question

Dr. Abubacker · Accepted Answer

(b) $m_{1}v = \left( m_{1} + m_{2} ight)v/3$
$3m_{1}v = m_{1}v + m_{2}v$
$3m_{1}v - m_{1}v = m_{2}v$
$2m_{1}v = m_{2}v$
$	herefore\ \frac{m_{2}}{m_{1}} = 2$

Q. A ball of mass $m_{1}$ is a moving with velocity $v$. It collides head on elastically with a stationary ball of mass $m_{2}$. The velocity of ball becomes $v/3$ after collision. Then the value of the ratio $\frac{m_{2}}{m_{1}}$ is

Explanation

Reviewed by Dr. Abubacker

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