Q. The distance between the centres of carbon and oxygen atoms in the carbon monoxide molecule is 1.130 $\mathring{\mathrm{A}}$. Locate the centre of mass of the molecule relative to the carbon atom.
A) 5.428 $\mathring{\mathrm{A}}$
B) 1.130 $\mathring{\mathrm{A}}$
C) 0.6457$\ \mathring{\mathrm{A}}$
D) 0.3260 $\mathring{\mathrm{A}}$
Explanation
(c) $X_{CM} = \frac{m_{1}x_{1} + m_{2}x_{2}}{m_{1} + m_{2}}$
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$\therefore$ $X_{CM} = \frac{(12 \times 0) + (16 \times 1.13)}{12 + 16} = 0.6457\mathring{\mathrm{A}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.