Q. A solid cylinder (SC) a hollow cylinder (HC) and a solid sphere (S) of the same mass and radius are released simultaneously from the same height of incline. The order in which these bodies reach the bottom of the incline is
A) SC, HC, S
B) SC, S, HC
C) S, SC, HC
D) HC, SC, S
Explanation
(c) Time taken in reaching bottom of incline is
$t = \sqrt{\frac{2l(1 + K^{2}/R^{2})}{g\sin\theta}}$
For solid cylinder (SC), $K^{2} = R^{2}/2$
For hollow cylinder (HC), $K^{2} = R^{2}$
For solid sphere (S), $K^{2} = \frac{2}{5}R^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.