(d) Angular momentum $L$ is given as
$L = \overrightarrow{r} \times \overrightarrow{p} = rp\sin\theta$
$\overrightarrow{r} =$ position vector of the particle $w.r.t.$ origin,
$\overrightarrow{p} =$ its linear momentum
$\overrightarrow{r} \times \overrightarrow{p}$ is maximum when $p$ is perpendicular to $r$
$i.e.\ \theta = 90{^\circ}$