Q. A disc is rolling (without slipping) on a horizontal surface. $C$ is its centre and $Q$ and $P$ are two points equidistant from $C$. Let $v_{P},v_{Q}$ and $v_{C}$ be the magnitude of velocities of points $P,Q$ and $C$ respectively, then
A) $v_{Q} > v_{C} > v_{P}$
B) $v_{Q} < v_{C} < v_{P}$
C) $v_{Q} = v_{P},v_{C} = \frac{v_{P}}{2}$
D) $v_{Q} < v_{C} > v_{P}$
Explanation
(a) Since disc is rolling (without slipping) about point $O$
Hence
$OQ > OC > OP$
$\therefore v = r\omega$
$\therefore v_{Q} > v_{C} > v_{P}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.