Q. The moment of inertia of a thin uniform rod length $L$ and mass $M$ about an axis passing through a point at a distance of 1/3 from one of its ends and perpendicular to the rod is
A) $\frac{{ML}^{2}}{12}$
B) $\frac{{ML}^{2}}{9}$
C) $\frac{{7ML}^{2}}{48}$
D) $\frac{{ML}^{2}}{48}$
Explanation
(b) $I_{CM} = \frac{ML^{2}}{12}$ (about middle point)
[image:7_image83.emf]
$\therefore$ $I = I_{CM} + Mx^{2}$
$= \frac{ML^{2}}{12} + M\left( \frac{L}{6} \right)^{2}$
$I = \frac{ML^{2}}{9}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.