Q. A particle of mass $m$ moves along line $PC$ with velocity $v$ as shown. What is the angular momentum of the particle about $O$
A) $mvL$
B) $mvl$
C) $mvr$
D) Zero
Explanation
(b) Angular momentum = linear momentum $\times$ Perpendicular distance of line of action of linear momentum from the axis of rotation $= mv \times l$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.