Q. A hoop of mass $M$ and radius $R$ is suspended to a peg in a wall. Its moment of inertia about the peg is
A) $2MR^{2}$
B) $MR^{2}$
C) $\frac{MR^{2}}{2}$
D) $\frac{3}{2}MR^{2}$
Explanation
(a) A hoop is a circular ring. Applying theorem of parallel axes,
$I = I_{0} + MR^{2} = MR^{2} + MR^{2} = 2MR^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.