Q. A constant torque of $31.4\ N - m$ is exerted on a pivoted wheel. If angular acceleration of wheel is $4\pi\ rad/s{ec}^{2}$, then the moment of inertia of the wheel is
A) $2.5\ kg - m^{2}$
B) $3.5\ kg - m^{2}$
C) $4.5\ kg - m^{2}$
D) $5.5\ kg - m^{2}$
Explanation
(a) $I = \frac{\tau}{\alpha} = \frac{31.4}{4\pi} = 2.5kg\ m^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.