Q. A cylinder rolls down an inclined plane of inclination $30{^\circ}$, the acceleration of cylinder is
A) $\frac{g}{3}$
B) $g$
C) $\frac{g}{2}$
D) $\frac{2g}{3}$
Explanation
(a) $a = \frac{g\sin\theta}{1 + \frac{K^{2}}{R^{2}}} = \frac{g\sin{30{^\circ}}}{1 + \frac{1}{2}} = \frac{g/2}{3/2} = \frac{g}{3}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.