Q. By keeping moment of inertia of a body constant, if we double the time period, then angular momentum of body

A) Remains constant
B) Becomes half
C) Doubles
D) quadruples
Explanation

(b) Angular of the body is given by
$L = I\omega$
or $L = I \times \frac{2\pi}{T}\ or\ \ L \propto \frac{1}{T}$
$\Rightarrow$ $\frac{L_{1}}{L_{2}} = \frac{T_{2}}{T_{1}}$
$\frac{L}{L_{2}} = \frac{2T}{T}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ $
$\ \ \ \ \ \ \ \ \ (As,\ T_{2} = 2T)$
So, $L_{2} = \frac{L}{2}$
Thus, on doubling the time period, angular momentum of body becomes half.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.