(d) ${\overrightarrow{v}}_{cm} = \frac{m_{1}{\overrightarrow{v}}_{1} + m_{2}{\overrightarrow{v}}_{2}}{m_{1} + m_{2}} = \frac{2 \times 3 + 3 \times 2}{2 + 3} = \frac{12}{5} = 2.4m/s$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.