Q. Moment of inertia of a circular loop of radius $R$ about the axis of rotation parallel to horizontal diameter at a distance $R/2$ from it is
A) $MR^{2}$
B) $\frac{1}{2}MR^{2}$
C) $2MR^{2}$
D) $\frac{3}{4}MR^{2}$
Explanation
(d) Applying theorem of parallel axes
$I = I_{0} + M(R/2)^{2} = \frac{1}{2}MR^{2} + \frac{MR^{2}}{4} = \frac{3}{4}MR^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.