The instantaneous angular-position of a point on a rotating wheel is given by the equation $ heta(t) = 2t^{3} - 6t^{2}$. The torque on the wheel becomes zero at

Question

The instantaneous angular-position of a point on a rotating wheel is given by the equation $	heta(t) = 2t^{3} - 6t^{2}$. The torque on the wheel becomes zero at

Dr. Abubacker · Accepted Answer

(b) Torque zero means, $\alpha$ zero
$	herefore\frac{d^{2}	heta}{dt^{2}} = 0 \Rightarrow 12t - 12 = 0$
$	herefore t = 1$ second

Q. The instantaneous angular-position of a point on a rotating wheel is given by the equation $\theta(t) = 2t^{3} - 6t^{2}$. The torque on the wheel becomes zero at

Explanation

Reviewed by Dr. Abubacker

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