(c) $I = \frac{2}{5}MR^{2} = \frac{2}{5}\left( \frac{4}{3}\pi R^{3}\rho \right)R^{2} = \frac{8}{15} \times \frac{22}{7}R^{5}\rho$ $I = \frac{176}{105}R^{5}\rho$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.