Q. A constant torque of $1000\ N$-$m$, turns a wheel of moment of inertia $200\ kg$-$m^{2}$ about an axis through the centre. Angular velocity of the wheel after $3\ s$ will be
A) $15\ rad/s$
B) $10\ rad/s$
C) $5\ rad/s$
D) $1\ rad/s$
Explanation
(a) $\alpha = \frac{\tau}{I} = \frac{1000}{200} = 5\ Rad/\sec^{2}$
From $\omega = \omega_{0} + \alpha t = 0 + 5 \times 3 = 15\ rad/s$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.