Q. The radius of gyration of a uniform rod of length $L$ about on axis passing through its centre of mass and perpendicular to its length is
A) $L/\sqrt{12}$
B) $L^{2}/12$
C) $L/\sqrt{3}$
D) $L/\sqrt{2}$
Explanation
(a) $I = MK^{2} = \frac{ML^{2}}{12}$
$\therefore K = \frac{L}{\sqrt{12}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.