(d) As $m_{1} = m_{2}\ \ \ \therefore\pi R_{1}^{2}xd_{1} = \pi R_{2}^{2}xd_{2}$
$\frac{R_{1}^{2}}{R_{2}^{2}} = \frac{d_{2}}{d_{1}}$
Now, $\frac{I_{1}}{I_{2}} = \frac{\frac{1}{2}mR_{1}^{2}}{\frac{1}{2}mR_{2}^{2}} = \frac{R_{1}^{2}}{R_{2}^{2}} = \frac{d_{2}}{d_{1}}$