Q. A system consists of three particles, each of mass $m$ and located at (1, 1) (2, 2) and (3, 3). The coordinates of the centre of mass are
A) (1, 1)
B) (2, 2)
C) (3, 3)
D) (6, 6)
Explanation
(b) $x = \frac{m_{1}x_{1} + m_{2}x_{2} + m_{3}x_{3}}{m_{1} + m_{2} + m_{3}} = \frac{m(1 + 2 + 3)}{3m} = 2$
Similarly, $y = \frac{m(1 + 2 + 3)}{3m} = 2$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.