Q. The total kinetic energy of rolling solid sphere having translational velocity $v$ is
A) $\frac{7}{10}mv^{2}$
B) $\frac{1}{2}mv^{2}$
C) $\frac{2}{5}mv^{2}$
D) $\frac{10}{7}mv^{2}$
Explanation
(a) $K_{N} = \frac{1}{2}mv^{2}\left( 1 + \frac{K^{2}}{R^{2}} \right) = \frac{1}{2}mv^{2}\left( 1 + \frac{2}{5} \right) = \frac{7}{10}mv^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.