Q. As a part of a maintenance inspection the compressor of a jet engine is made to spin according to the graph as shown. The number of revolutions made by the compressor during the test is
A) 9000
B) 16570
C) 12750
D) 11250
Explanation
(d) No of revolution = Area of trapezium
$= \frac{1}{2} \times (2.5 + 5) \times 3000 = 11250rev$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.