(a) $\frac{1}{2}mv^{2}\left( 1 + \frac{K^{2}}{R^{2}} \right) = \frac{1}{2}(0.5)(0.2)^{2}\left( 1 + \frac{2}{5} \right) = 0.014\ J$
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Ph.D. in Physics with 19+ years of teaching experience.