Q. A solid cylinder of mass $M$ and radius $R$ rolls without slipping down an inclined plane of length $L$ and height $h$. What is the speed of its centre of mass when the cylinder reaches its bottom
A) $\sqrt{\frac{3}{4}gh}$
B) $\sqrt{\frac{4}{3}gh}$
C) $\sqrt{4gh}$
D) $\sqrt{2gh}$
Explanation
(b) $v = \sqrt{\frac{2gh}{1 + \frac{K^{2}}{R^{2}}}} = \sqrt{\frac{2gh}{1 + \frac{1}{2}}} = \sqrt{\frac{4}{3}gh}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.