(c) $a = \frac{g}{1 + \frac{K^{2}}{R^{2}}}$ [For solid cylinder $\frac{K^{2}}{R^{2}} = \frac{1}{2}$] $\therefore a = \frac{g}{1 + \frac{1}{2}} = \frac{2}{3}g$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.