(c) $\frac{Rotational\ kinetic\ energy}{Translatory\ kinetic\ energy} = \frac{\frac{1}{2}mv^{2}\frac{K^{2}}{R^{2}}}{\frac{1}{2}mv^{2}} = \frac{K^{2}}{R^{2}} = \frac{2}{5}$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.