(c) $\overrightarrow{\tau} = \overrightarrow{r} \times \overrightarrow{F} = r\ F\sin{\phi\ \therefore\tau = rF\sin\phi}$ $F\sin\phi =$ transverse component of force $F\cos\phi =$ radial component of force
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.