The M.I. of a body about the given axis is $1.2\ kg imes m^{2}$ initially the body is at rest. In order to produce a rotational kinetic energy of $1500\ J$, an angular acceleration of $25\ rad/s{ec}^{2}$ must be applied about that axis for duration of

Question

The M.I. of a body about the given axis is $1.2\ kg 	imes m^{2}$ initially the body is at rest. In order to produce a rotational kinetic energy of $1500\ J$, an angular acceleration of $25\ rad/s{ec}^{2}$ must be applied about that axis for duration of

Dr. Abubacker · Accepted Answer

(b) Rotational kinetic energy $= \frac{1}{2}I\omega^{2} = 1500$
$\Rightarrow \frac{1}{2} 	imes 1.2 	imes \omega^{2} = 1500$
$\Rightarrow \omega^{2} = \frac{3000}{1.2} \Rightarrow \omega = 50\ rad/s$
Initially the body was at rest and after $t\ sec$ its angular velocity becomes $50\ rad/s$
$\omega = \omega_{0} + \alpha t \Rightarrow 50 = 0 + 25 	imes t \Rightarrow t = 2s$

Q. The M.I. of a body about the given axis is $1.2\ kg \times m^{2}$ initially the body is at rest. In order to produce a rotational kinetic energy of $1500\ J$, an angular acceleration of $25\ rad/s{ec}^{2}$ must be applied about that axis for duration of

Explanation

Reviewed by Dr. Abubacker

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