Q. A wheel of mass $10\ kg$ has a moment of inertia of $160\ kg$-$m^{2}$ about its own axis, the radius of gyration will be
A) $10\ m$
B) $8\ m$
C) $6\ m$
D) $4\ m$
Explanation
(d) $I = MK^{2} = 160 \Rightarrow K^{2} = \frac{160}{M} = \frac{160}{10} = 16 \Rightarrow K = 4metre$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.