Q. An inclined plane makes an angle of $30{^\circ}$ with the horizontal. A solid sphere rolling down this inclined plane from rest without slipping has a linear acceleration equal to
A) $\frac{g}{3}$
B) $\frac{2g}{3}$
C) $\frac{5g}{7}$
D) $\frac{5g}{14}$
Explanation
(d) $a = \frac{g\sin\theta}{1 + \frac{K^{2}}{R^{2}}} = \frac{g\sin\theta}{1 + \frac{2}{5}} = \frac{g/2}{7/5} = \frac{5g}{14}$
As $\theta = 30{^\circ}$ and $\frac{K^{2}}{R^{2}} = \frac{2}{5}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.