Q. A constant torque of $1000\ N$-$m$ turns a wheel of moment of inertia $200kg$-$m^{2}$ about an axis through its centre. Its angular velocity after $3\ sec$ is
A) $1\ rad/sec$
B) $5\ rad/sec$
C) $10\ rad/sec$
D) $15\ rad/sec$
Explanation
(d) $\omega = \omega_{0} + \alpha t \Rightarrow \omega = 0 + \left( \frac{\tau}{I} \right)t$ [As $\tau = I\alpha$]
$\omega = 0 + \frac{1000}{200} \times 3 = 15rad/s$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.