Q. A circular disc of mass $0.41\ kg$ and radius $10\ m$ rolls without slipping with a velocity of $2\ m/s$. The total kinetic energy of disc is
A) $0.41\ J$
B) $1.23\ J$
C) $0.82\ J$
D) $2.4\ J$
Explanation
(b) $K_{N} = \frac{1}{2}mv^{2}\left( 1 + \frac{K^{2}}{R^{2}} \right) = \frac{1}{2} \times 0.41 \times (2)^{2} \times \left( \frac{3}{2} \right) = 1.23\ J$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.