Q. An inclined plane makes an angle of $30{^\circ}$ with the horizontal. A solid sphere rolling down the inclined plane from rest without slipping has a linear acceleration equal to
A) 5 g/14
B) 5 g/4
C) 2 g/3
D) g/3
Explanation
(a) $a = \frac{g\sin\theta}{1 + I/mr^{2}} = \frac{g\sin{30{^\circ}}}{1 + \frac{2}{5}} = \frac{5}{7}g \times \frac{1}{2} = \frac{5g}{14}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.