Q. A thin uniform circular ring is rolling down an inclined plane of inclination $30{^\circ}$ without slipping. Its linear acceleration along the inclined plane will be
A) $g/2$
B) $g/3$
C) $g/4$
D) $2g/3$
Explanation
(c) $a = \frac{g\sin\theta}{1 + \frac{K^{2}}{R^{2}}} = \frac{g\sin{30{^\circ}}}{1 + 1} = \frac{g}{4}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.