Q. Radius of gyration of uniform thin rod of length $L$ about an axis passing normally through its centre of mass is
A) $\frac{L}{\sqrt{12}}$
B) $\frac{L}{12}$
C) $\sqrt{12}\ L$
D) $12\ L$
Explanation
(a) $\frac{ML^{2}}{12} = MK^{2} \Rightarrow K = \frac{L}{\sqrt{12}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.