(b) As shown in figure normal reaction $R = mg$. Frictional force $F = \mu R = \mu\ mg$. To topple, clockwise moment must be more than the anticlockwise moment $ie,\ \mu mg \times \frac{h}{2} > mg \times \frac{a}{2}mg \times \frac{a}{2}\ or\ \mu > a/h$
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