Q. If rotational kinetic energy is 50% of translational kinetic energy, then the body is
A) Ring
B) Cylinder
C) Hollow sphere
D) Solid sphere
Explanation
(b) $K_{R} = 50\%,\ K_{T}$
$\frac{1}{2}mv^{2}\left( \frac{K^{2}}{R^{2}} \right) = \frac{50}{100} \times \frac{1}{2}mv^{2} \Rightarrow \ \ \therefore\frac{K^{2}}{R^{2}} = \frac{1}{2}$
$i.e.$ body will be solid cylinder
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.