(d) $\tau = \mathbf{r \times F}$
$\tau$ is perpendicular to both $\mathbf{r}\ and\ \mathbf{F}$, so $\mathbf{r}.\tau\ as\ well\ as\mathbf{\ F}.\tau$ has to be zero.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.